中学数学中的第三个数学绝世奇迹 |
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来源:不详 更新时间:2011-9-3 11:17:14 |
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sin∠4。)·
(sin∠1。/sin∠12)·(sin∠11。/sin∠17)=(sin∠9/sin∠4)·(sin∠11/sin∠12)·
(sin∠16/sin∠3)·(sin∠1/sin∠17)=
(sin∠9/sin∠4)·(sin∠11/sin∠12)·(FG/CG)·(CE/EF)=(BG/CG)×(sin∠9/sin∠4)
·(FG/BG)×(sin∠11/sin∠12)·
(DE/EF)·(CE/DE)=(BG/CG)×(FH/BH)·(DM/MF)×(CE/DE)=(sin∠2/sin∠3)
·(BF/CF)×(FH/BH)·(DM/MF)×
(sin∠1/sin∠2)·(CF/DF)=(sin∠1/sin∠3)×(BF/BH)×(DM/DF)·(FH/MF)=(sin∠1/
sin∠3)×(sinα/sinθ)·(AF/AH)×
(sinφ/sinα)·(AM/AF)·(FH/MF)=(sin∠1/sin∠3)·(sinφ/sinθ)
·(AM/MF)·(FH/AH)=
(sin∠1/sin∠3)·(sinφ/sinθ)·(sin∠3/sinγ)·(sinβ/sin∠1)=(sinβ·sinφ)/(
sinγ·sinθ)=1。由解㈠※。证毕。
(解三)由(DF/DM)×(BG/BC)×(AH/GH)×(ME/AE)×(AC/AF)=(sinα/sinφ)·(AF/AM)×
(sin∠2/sin∠1。)·(GF/CF)×(sin∠2/sin∠1。)·(GF/CF)×(sin∠1/sin∠2)
·(AF/GF)×(sin∠2/sin∠1。)·(MF/AF)×(AC/AF)=(sinα/sin∠1)·(DE/sinφ)·
(sin∠2/DE)·(MF/AM)×(AC/CF)=(sinα/sin∠1)·(AD/sin∠11)·(sin∠15。/DF)·
(sinγ/sin∠3)×(sin∠15。/DF)·(sinγ/sin∠3)×(sin∠11/sin∠15)
·(AE/EF=)(sin∠1/sinγ)=
(sinα/sin∠3)(AD/DF)=(sinα/sin∠3)·(sin∠3/sinα)=1⑴。
由⑴→1=(DF/DM)×(BG/BC)×(AH/GH)×(ME/AE)×(AC/AF)=(sinα/sinφ)·(AF/AM)×(sinθ/
sinα)·(AG/AC)
×(sin∠1/sin∠2)·(AF/GF)×(sin∠2/sin∠1。)·(MF/AF)×(AC/AF)=(sinθ/sinφ)
·(AG/GF)·(MF/AM)=
(sinθ/sinφ)·(sin∠3/sinβ)·(sinγ/sin∠3)=(sinθ/sinφ)·(sinγ/
sinβ)=1。由解㈠※。证毕。
(解四)由1=(sin∠3。/sin∠2)·(CF/EF)×(sin∠1/sin∠3。)·(FH/FG)×(sin∠2/sin∠1。)
·(GF/CF)×(EF/FH)=
(CD/DE)×(AH/AG)×(BG/BC)×(EF/FH)=(sinα/sinφ)·(AC/AE)×(AH/AG)×(sinθ/sinα)
·(AG/AC)×(sinγ/sinβ)
·(AE/AH)=(sinθ/sinφ)·(sinγ/sinβ=1⑴。由解㈠※。证毕。
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上一个数学: 数学笑话 下一个数学: 非等差数列巧求和 |
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